Write a c program to enter the array of 10 integer numbers and print the smallest number.


 #include<stdio.h>
#include<conio.h>
void main() 
{
 int num[10];
 int temp=0,i;
 printf("enter the numbers");
 for(i=0;i<10;i++) 
 scanf("%d",&num[i]);
 temp=num[0];
 for(i=1;i<10;i++) 
  {
    if(num[i]<temp) 
       temp=num[i];
  }
 printf("\n smallest number=%d",temp);
 getch();
}

Output:
enter the numbers
23 42 67 89 66 45 78 55 34 77
smallest number=23

Explanation:
  
 The program is to take an input of an integer array and print the smallest number in the array. 
 
num[10] is the integer array of size 10.
Variable i is taken as a subscript, and variable temp, which is initialized as zero, is taken as a temporary variable. 
Run time input of array is taken using subscript "i" from 0 to 9. 
If you have any Misconceptions related to for-loop, follow the below link, 

Now, we have to find the smallest number among the array of 10 numbers, 
Initialize temp as array[0].
temp=array[0].

Use the for loop to run the entire loop. 
Inside for loop, we are using the if-statement to compare two int values. 
This for-loop will run from num[1] to num[9].
The value of num[0] is stored in the temp variable. 
This will save one iteration of for loop. 
 
At each iteration, num[i] is compared with the temp variable in the if-statement. 
If num[i] is smaller than the temp variable, then the value of num[i] will be stored in temp. Otherwise, the loop will continue forward. 
In this way, the temp will get the smallest number from the array.